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 Equation Problem.....

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Posted on 06-07-07 7:16 AM     Reply [Subscribe]
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Maths teacher has drawn following equation on the board:
____ + ____ = ____
The teacher then asked students to put two digits on each line to make a valid equation. But they can use digits 1 to 6, each once and only once.

How can it be done? I got one answer, lets see if more than one is possible!!!

Hint:Please avoid Brute Force!!!
 
Posted on 06-07-07 7:34 AM     Reply [Subscribe]
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4^1 + 2^ 5 = 36

Is this valid, Thyanboche?

~@~
 
Posted on 06-07-07 7:35 AM     Reply [Subscribe]
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Duh ----" Thayngboche "-- Sorry, missed the 'g' ~
 
Posted on 06-07-07 7:39 AM     Reply [Subscribe]
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Saajha Dude -

4^1 + 2^ 5 = 36
=> 4^1 + 2^5 = 6^2

The teacher asked - "But they can use digits 1 to 6, each once and only once".

Count your '2'.

All the Best!!!
 
Posted on 06-07-07 8:18 AM     Reply [Subscribe]
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hmm...OK, Try this:

1^4 + 35 = 6^2

Are you gonna say 1^4 = 1X1X1X1 and hence 1 occured 4 times? ;)
~@~
 
Posted on 06-07-07 8:59 AM     Reply [Subscribe]
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Saajha-
Your equation includes 35 and not 3,5. We can use only 1-6!!!!

Question:Are you gonna say 1^4 = 1X1X1X1 and hence 1 occured 4 times?
Answer:1^4 is treated as 1,4 exactly once.

U r applying brute force.
 
Posted on 06-07-07 10:09 AM     Reply [Subscribe]
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Here it goes:
1^3+4*2 = 6+5
11=11
 
Posted on 06-07-07 10:13 AM     Reply [Subscribe]
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Here is the solution

Sqrt(5^4)+2^1=Sqrt(3^6)
 
Posted on 06-07-07 10:26 AM     Reply [Subscribe]
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^ how valid is that. what about the negative values of the square roots.
 
Posted on 06-07-07 11:01 AM     Reply [Subscribe]
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if you are asking for 1 thru 6 how can you put root symbols and square root.
you should have mentioned this in the begining.

dummy question.
"to put two digits on each line " that means you can only put two digits not other words and symbols.
 
Posted on 06-07-07 11:18 AM     Reply [Subscribe]
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.tregor
it shoud be (3^1)+(4*2) = (6+5)
or (3*1)+(4*2) = (6+5)

other solution
(4/2) + (6*1) = (5+3)
(5+2)+(-6/3) = (4+1)
(5+2)+(6-3) = (4*1)
(5+3)+(-6+2) =(4*1)
(6+5)+(-3*2) = (4+1)
(3*2)+(4+1) = (6+5)
(3*2)+(-4-1)=(6-5)

and it goes on
 
Posted on 06-07-07 3:59 PM     Reply [Subscribe]
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Posted on 06-07-07 4:15 PM     Reply [Subscribe]
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The right answer is
1x2 + 3x6 = 4x5
 
Posted on 06-07-07 4:16 PM     Reply [Subscribe]
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where is thyangboche?
 
Posted on 06-07-07 4:35 PM     Reply [Subscribe]
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my bad
typing mistake
I meant 1*3+4*2 = 6+5
 
Posted on 06-07-07 9:41 PM     Reply [Subscribe]
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Tregor, Parbatya and Prakashji
All are correct!

'BUT' I appreciate 1x2 + 3x6 = 4x5 (Parbatya) answer. The reason behind there's a uniformity in his solution. The operation he uses is very readable.

'Again' it's upto you!!!

Another example could be -
(5/6) + (1/2) = (4/3)
LHS = {(5+3)/6}
=8/6
=4/3
Thus RHS!!!

Thanks for brainstroming and your commendable effort!!!
 
Posted on 06-08-07 1:45 AM     Reply [Subscribe]
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_ _

X _
_______
_ _
+ _ _
_______
_ _

There are 9 blank spaces. The upper one (X) is multiply and the lower one (+) is addition. You Need to fill the blanks with the number 1 to 9 without repeating.
Note: "without repeating"

Hint final answer is 9 3

Good luck
 
Posted on 06-08-07 2:08 AM     Reply [Subscribe]
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Manwithmission -

_ _

X _
_______
_ _
+ _ _
_______
_ _


Are u sure this structure is the one and valid with (1-9 value to balance 93 as the final value) Right Alignment?

_ _

X _
_______
_ _
+ _ _
_______
_ _


Which is the right Figure??? Are u sure u r right??? If not do the necessary change!!!
 
Posted on 06-08-07 2:36 AM     Reply [Subscribe]
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17
x 4
-------------
68
+ 25
------------
93

Manwithmission, check the answer!!!
 
Posted on 06-08-07 9:36 AM     Reply [Subscribe]
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gr8
Thyangboche
 



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